let 2x+5y=12......... equation I
also,4x+3y=-4........ equation ii
now, multiply equation i by 2
we get,2(2x+5y=12)
or,4x+10y=24
now subtract i from ii
4x+10y=24
-4x+3y=-4
so,the answer be 7y=28
or,y=4
now putting the value of y in equation I we get,
4x+10y=24
or,4x+10.4=24
or, 4x=24-40
or, 4x=16
or,x=4
therefore, the value of x and y are 4and 4
