Respuesta :

Alfpfeu

Answer:

[tex]\boxed{\sf \ \ \ (x-1)(x-3)(x+5) \ \ \ }[/tex]

Step-by-step explanation:

Hello,

1 is a trivial zero so we can write

[tex]x^3+x^2-17x+15=(x-1)(x^2+2x-15) = (x-1)(x^2+5x-3x-15)\\==(x-1)(x(x+5)-3(x+5))=(x-1)(x-3)(x+5)[/tex]

hope this helps
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