Sarco06
Sarco06 Sarco06
  • 03-06-2020
  • Mathematics
contestada

x^3+3y-xy' = 0

dy/dx = xy^3-xy

Respuesta :

Аноним Аноним
  • 03-06-2020

Answer:

dy/dx = xy^3-xy   =

y = ± √2 = ± 1.4142

x  =  0

y  =  0

Step-by-step explanation:

Step  1  : Simplify y/d

Step  2  :  See below

Step  3  :  See below

Pulling out like terms

Trying to factor as a Difference of Squares

Answer:  

y = ± √2 = ± 1.4142

x  =  0

y  =  0

Hope this helps.

Answer Link

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