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A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to 1.3 atm, and the temperature of the gas increases to 285 K.

Respuesta :

olemakpadu
Would presume you are asked to find the volume, since there is no second volume.

By General Gas Law:

P₁V₁/T₁ = P₂V₂/T₂

1.6 * 168 /255 = 1.3*V₂/285

V₂ = 1.6 * 168 * 285 / (1.3*255)

V₂ = 231.095

Final volume ≈ 231 cm³

Answer: The final volume is  [tex]231cm^3[/tex]

Explanation: Using ideal gas equation:

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

[tex]P_1[/tex]= initial pressure = 1.6 atm

[tex]V_1[/tex]= initial volume = [tex]168cm^3[/tex]

[tex]T_1[/tex]= initial temperature = 255 K

[tex]P_2[/tex]= final pressure= 1.3 atm

[tex]V_2[/tex]= final volume = ?

[tex]T_2[/tex]= final temperature = 285 K

[tex]\frac{1.6\times 168}{255}=\frac{1.3\times V_2}{285}[/tex]

[tex]V_2=231cm^3[/tex]